We looked at factoring today for trinomials with a =1 in the form ax^2 + bx + c. (hence, x^2 + bx + c).
Practice:
Chapter 5.3 Page 95 # 4, 5, 8, 9, 13(a), 15(a)
Puzzle 53: Cross-Number Puzzle
Practice:
Chapter 5.3 Page 95 # 4, 5, 8, 9, 13(a), 15(a)
Puzzle 53: Cross-Number Puzzle